Question

at Score: 64% Resources I dive Up? Hint of 20 > Consider the reaction. 2 H, +0, 2H, 0 AH = - 484 kJ Which answer best describes the transfer of heat that occurs when 1.31 mol H, reacts with 0.624 mol O,? O 317 kJ released O 302 kJ absorbed 302 kJ released O 484 kJ released 317 kJ absorbed 484 kJ absorbed

Answer 1

Answer :

Option (3) 302 KJ released

From the reaction , 1 mole of O​​​​​​2 and 2 mole of H​​​​​​2 combine to form water and releases 484 KJ of energy ( -ve sign indicate energy is released) .

Now , available mole of O​​​​​​2 = 0.624 mole

1 mole of O​​​​​​2 required = 2 mole of H​​​​​​2

0.624 mole of O​​​​​​2 required = 2 * 0.624 = 1.248 mole of H​​​​​​2

But available mole of H​​​​​​2 is 1.31 mole . It means H​​​​​​2 is in excess . So, limiting Reagent is O​​​​​​2 .

Further calculation is done on the available mole of O​​​​​​2

1 mole of O​​​​​​2  in the reaction release energy = 484 KJ

0.624 mole of O​​​​​​2 in the reaction release energy = 484 * 0.624 = 302 KJ

So, 302 KJ of energy is released