for the following solve: A. Given that the solubility of Ca3(PO4)2 is 7.26 × 10-5 g...
for the following solve:
A. Given that the solubility of Ca3(PO4)2 is 7.26 × 10-5 g L-1 at a certain temperature, calculate the pKsp of calcium phosphate. Report your answer to 4 significant digits. Note that the pKsp = -log(Ksp).
B. Calculate the solubility (in grams per liter) of CuCl using the Ksp value 4.75 x 10-7 at a certain temperature. Report your answer to 3 significant digits, but do NOT include units.
Homework Answers
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for the following solve:
A. Given that the solubility of
Ca3(PO4)2 is 7.26 ×
10-5 g...
what is the molar solubility of Ca2+ in a 1.00 M aqueous solution of Ca3(PO4)2 (Ksp...
what is the molar solubility of Ca2+ in a 1.00 M aqueous solution of Ca3(PO4)2 (Ksp for calcium phosphate is 2.0 x 10^-29)
Calculate the solubility of Ca3(PO4)2 in a solution containing 0.0539 M Na3PO4. Ksp=2.0*10^-29 for Ca3(PO4)2
Calculate the solubility of Ca3(PO4)2 in a solution containing 0.0539 M Na3PO4. Ksp=2.0*10^-29 for Ca3(PO4)2
Show calculations for Calcium phosphate molar solubility. Ca3(PO4)2. ksp = 2.08 x 10^-33. Can you please...
Show calculations for Calcium phosphate molar solubility. Ca3(PO4)2. ksp = 2.08 x 10^-33. Can you please show me how you get from one step to the next? thanks!
The Ksp of Ca3(PO4)2 is 1x 10-33. What is the solubility in moles per liter (mol/L)...
The Ksp of Ca3(PO4)2 is 1x 10-33. What is the solubility in moles per liter (mol/L) of Ca3(PO4)2 (s) in a 0.01 M Ca(NO3)2 (aq) solution? (Note: The molar mass of Ca3(PO4)2 is not needed in this problem, which asks for moles per L.) a. 3.2 x 10-14 mol/L b.3.0 x 10-15 mol/L c. 9.8 x 10 mol/L d. 1.6 x 10-14 mol/L e. 5.0 x 10-32 mol/L
The solubility of calcium sulfate at a given temperature is 0.02005 g/L. Calculate the Ksp at...
The solubility of calcium sulfate at a given temperature is 0.02005 g/L. Calculate the Ksp at this temperature. After you get your answer, take the negative log and enter that (so it's like you're taking the pKsp). (Note: sulfate ion molar mass = 96.07 g/mol)
Calculate the solubility of barium phosphate, Ba3(PO4)2 in units of grams per liter. Ksp(Ba3(PO4)2) = 1.3E-29.
Calculate the solubility of barium phosphate, Ba3(PO4)2 in units of grams per liter. Ksp(Ba3(PO4)2) = 1.3E-29.
QUESTION 17 1 point The solubility of calcium sulfate at a given temperature is 0.02005 g/L....
QUESTION 17 1 point The solubility of calcium sulfate at a given temperature is 0.02005 g/L. Calculate the Ksp at this temperature. After you get your answer, take the negative log and enter that (so it's like you're taking the pksp). (Note: sulfate ion molar mass = 96.07 g/mol)
1. Calculate the solubility (in grams per liter) of Fe(OH)3 , which has a Ksp of...
1. Calculate the solubility (in grams per liter) of Fe(OH)3 , which has a Ksp of 4.01 x 10-15 at a given temperature. Report your answer to 3 significant digits, but do NOT include units. 2. What is the solubility of Ag2CO3 (in milligrams (mg) per liter) in an aqueous solution of 0.15 M Na2CO3? Report your answer to 2 decimal places, but do NOT include units!
A chemist fills a reaction vessel with 0.980 g calcium phosphate (Ca3(PO4)2) solid, 0.212 M calcium...
A chemist fills a reaction vessel with 0.980 g calcium phosphate (Ca3(PO4)2) solid, 0.212 M calcium (Ca+2) aqueous solution and 0.119 M phosphate (PO4−3) aqueous solution at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy ΔG for the following chemical reaction: Ca3(PO4)2(s) 3Ca+2(aq)+2PO4−3(aq) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule.
Given that the solubility reaction for calcium phosphate is Ca3(PO4)2(s) = 3Ca2+ (aq) + 2PO43- (aq)...
Given that the solubility reaction for calcium phosphate is Ca3(PO4)2(s) = 3Ca2+ (aq) + 2PO43- (aq) why does the addition of acid increase the solubility of calcium phosphate? View Available Hint(s) O It decreases the phosphate ion concentration, forcing the equilibrium to the right It decreases the phosphate ion concentration, forcing the equilibrium to the left. O It increases the phosphate ion concentration, forcing the equilibrium to the right. It increases the phosphate ion concentration, forcing equilibrium to the left....
The Ksp of Ca3(PO4)2 is 1x 10-33. What is the solubility in moles per liter (mol/L) of Ca3(PO4)2 (s) in a 0.01 M Ca(NO3)2 (aq) solution? (Note: The molar mass of Ca3(PO4)2 is not needed in this problem, which asks for moles per L.) a. 3.2 x 10-14 mol/L b.3.0 x 10-15 mol/L c. 9.8 x 10 mol/L d. 1.6 x 10-14 mol/L e. 5.0 x 10-32 mol/L
The solubility of calcium sulfate at a given temperature is 0.02005 g/L. Calculate the Ksp at this temperature. After you get your answer, take the negative log and enter that (so it's like you're taking the pKsp). (Note: sulfate ion molar mass = 96.07 g/mol)
QUESTION 17 1 point The solubility of calcium sulfate at a given temperature is 0.02005 g/L. Calculate the Ksp at this temperature. After you get your answer, take the negative log and enter that (so it's like you're taking the pksp). (Note: sulfate ion molar mass = 96.07 g/mol)
Given that the solubility reaction for calcium phosphate is Ca3(PO4)2(s) = 3Ca2+ (aq) + 2PO43- (aq) why does the addition of acid increase the solubility of calcium phosphate? View Available Hint(s) O It decreases the phosphate ion concentration, forcing the equilibrium to the right It decreases the phosphate ion concentration, forcing the equilibrium to the left. O It increases the phosphate ion concentration, forcing the equilibrium to the right. It increases the phosphate ion concentration, forcing equilibrium to the left....
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