Homework Answers
Answer
0.222 J/g℃
Explanation
Heat absorbed by water = heat released by metal
Heat change of metal (qlost) = m × ∆T × Cs
m = mass of water , 180.0g
∆T = Temperature difference of metal , 33.0℃ - 100℃ = -67.0℃
Cs = specific heat capacity of metal
qlost= 180.0g × -67.0℃ × Cs = -12060g℃ × Cs
Heat change of water ( qgained)
qgained = m × ∆T × Cs
= 80.0g × (33.0℃ - 25.0℃ ) × 4.184J/g℃
= 2677.76J
qlost = - qgained
-12060g℃×Cs= - 2677.76J
Cs = 0.222J/g℃
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