Question

Calculate the pH of a solution prepared by adding 20.0 mL of 0.100 M HCl to 80.0 mL of a buffer that is comprised of 0.25 M NH3 and 0.25 M NH4Cl. Kb of NH3 = 1.8 x 10-5. ОА. 9.17 ОВ. 4.83 0 o С. 9.34 OD.9.26 OE. 4.66

Answer 1

[NHK] / [NH, PH] = 0.25M CNA, C 30 CM, Jo 0.25M (Aqueous solution of Basic Buffer - (80 ml) NHy is NHL OM) (Ka Ng/NW, OH = 1,8x1067 - Tatal volume after miring = loome [Hel] = CHF] = Londo-lM zome . do, Neobalisation reaction, from Nhp ce brom Hue - 7 WHY I tho, kegalkon I NH₂ OH + HAY - 80x0.25 20xool tzo loo treaction proceeds (KDN HOM Kw Ab loo Jox0.25 los forward) 2 Dessociation Censtant of - Water limiting reagent - 21.04789 20-2 10-14 2012 Neutralisation At 22 2% -* } Hydrolysis by Nity a 12 ŽIR yonlysis by Nha Too los co (conjugate aced of weak

2) Reg el8x102 = 22 Loox 18 too the [14] ve 22 – 11019 18 x 1.8 CM7) 2 0.679 X70-9M pH = -log Cht] o 9.17 to, Part A i Correct