Question

U. A solution is prepared by dissolving 50.0 g cesium chloride in 50.0 g water. The volume of the solution is 63.3 mL. Calculate the mass percent, molarity, molality, and mole fraction of the cesium chloride.

Im sorry please ignore the first 2

Answer 1

3) total mass of solution = (50 + 50) = 100 g

mass percent of CsCl = (50 / 100) * 100 = 50 %

mole of CsCl = mass / molar mass = 50 g / 168.36 g/mole = 0.297 mole.

molarity = 0.297 mole / 0.0633 L = 4.69 M

and

molality = 0.297 mole / 0.050 Kg = 5.94 mole / Kg

mole of water = 50.0 g / 18 g / mole = 2.78 mole.

mole fraction of CsCl = 0.297 mole / (2.78 + 0.297) mole = 0.0966

2) option (d) is the answer.

because there are 11 g > 10 g remain in 100 g water.

Hence some solute are precipitated.

so

it is super saturated solution.