The initial volume of water = 25ml
final volume of water = 34.3ml
The volume of metal = final volume of water -The initial volume of water
= 34.3-25 = 9.3ml
The density of metal = 5.27g/ml
mass of metal = volume of metal * density
= 9.3*5.27 = 49.011g
mass of water = volume of water * density
= 25*1 = 25g
Heat lose of metal = Heat gain of water
mcT = mcT
49.011*c*(153-37.3) = 25*4.184*(37.3-25)
c = 0.23J/g-0C
The specific heat of unknown metal = 0.23J/g-0C>>>>answer
Assignment Score: 65.7% Resources Give Up? Mint Check Answer Question 31 of 35 > 150 An...
nment Score: 1438/2000 Resources Ex Give Up? Feedback Resume estion 3 of 20 > Attempt 1 - An irregular lump of an unknown metal has a measured density of 2.50 g/mL. The metal is heated to a temperature of 153 °C and placed in a graduated cylinder filled with 25.0 mL of water at 25.0 °C. After the system has reached thermal equilibrium, the volume in the cylinder is read at 33.2 mL, and the temperature is recorded as 37.9...
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An irregular lump of an unknown metal has a measured density of 3.19 g/mL. The metal is heated to a temperature of 153°C and placed in a graduated cylinder filled with 25.0mL of water at 25.0°C. After the system has reached thermal equilibrium, the volume in the cylinder is read at 30.0mL, and the temperature is recorded as 37.1°C. What is the specific heat of the unknown metal sample? Assume no heat is lost to the surroundings. c=_____________J/g*C