Question

What is E°_cell for the following hypothetical reaction exactly as written (in volts), given the standard electrode potential (E°) values below?

X_(s) + Y²⁺_(aq) → X²⁺_(aq) + Y_(s)

X²⁺_(aq) + 2 e^- → X_(s)   E° = -0.99 V

Y²⁺_(aq) + 2 e^- → Y_(s)   E° = -2.25 V

Answer 1

E con 1 Ereduction + E'oxidation The given reaction Xos+ y2 +22) → went Yes The half-reaction for each process, Xoss → than t 2e7 . y + the Xis" In question given that locess Ereduction of y2+ = -2.25 V E reduction of x2+ 2 - 0.990 Here given El reduction of x 2t but here we need to the oxidation value so we know that Eloxidation - Eoreduction => E°oxidation x 2 - Ereduction x t =:-(-0.99) - 0.99V tedy

Eredundian ok y 27 - 2:25 V E oxidation of x = 0.997 E ceu = E preduation of meat + E oxidation of * = -2.251 +0.9911