Question

When 5.00 g of KClO3 is heated it decomposes according to the equation: 2KCIO3 ---> 2KCI + 302 a) Calculate the theoretical yield of oxygen b) Give the % yield if 1.78 g of O2 is produced. c) How much Oz would be produced if the percentage yield was 78. 1 i.FT BIO E Eng

Answer 1

Giren, 122.55 on heating kelo, decomposes as 2. 00₂ - 2kel. +302 We know molecular weight of KClO₂ is 122.55 g / mot Hence, 5g of KelO3 = 5 = 4.08x102 mot. From the equation, it is clear that, from a moles of kelos, 3 moles of O2 is generated on heating. Hence, from 4:08+.102 mot of kelo3, O2 will generate - 4.08x102x3 = 6*12x10² mot Hence, the theoratical yeild of Oz is = 6.12 x 15² x 32 g = 1.96 g

= 1.464 Answer-6 If 1178 g of O, is produced from 5.00 g of kolo, on heating Percentage of yeild = 17 8 x 100% = 90.8 %. Answer-c If the percentage of yeild was 78.5% Let, ag of Oz is produced, 2 *100. = 78.5%. x= 78.5 x 1.96 = 1.54 g 1.96 100 100 produce if the percentage of 1.54 g of Oz will Yeild is 78.5%