Question 9 A mixture which contains 0.960 M PCl3 and 0.730 M Cl2 is placed in...
Consider the following reaction: PCl5(g)⇌PCl3(g)+Cl2(g) a. Initially, 0.62 mol of PCl5 is placed in a 1.0 L flask. At equilibrium, there is 0.20 mol of PCl3 in the flask. What is the equilibrium concentration of PCl5? Express your answer to two significant figures and include the appropriate units. b. What is the equilibrium concentration of Cl2? Express your answer to two significant figures and include the appropriate units. c. What is the numerical value of the equilibrium constant, Kc, for...
Consider the following reaction where Kc = 1.20x10-2 at 500 K: PCl; (g)PCl3 (g) + Cl2 (g) A reaction mixture was found to contain 0.125 moles of PCls (2),4.99-102 moles of PCl3 (g), and 4.1 Indicate True (T) or False (F) for each of the follow ー▼ I. In order to reach equilibrium PC15(g) must be produced in a ▼ 2. In order to reach equilibrium Kc must decrease ▼ 3. In order to reach equilibrium PC13 must be consumed...
ampere The reaction, PCls (g) 5 PC13(g) + Cl2(g), has Kc = 4.20 x 102. If 0.1050 mol of PCL5, 0.0450 mol of Cl2 and 0.0450 mol of PCl3 is placed in a 0.5000-L flask at 250°C, what are the equilibrium concentrations of PCl3 and Cl, if equilibrium (PCI5] = 0.2065 M? A) [PC13] = 0.00350 M; (Cl2] = 0.00350 M B) [PC13] = 0.0900 M; [Cl2] = 0.0900 M -=51,85 (66450) (19450) C) [PC13] = 0.2100 M; [Cl2] =...
Consider the reaction. PCl5(g)−⇀↽−PCl3(g)+Cl2(g)Kc=0.0420 The concentrations of the products at equilibrium are [PCl3]=0.180 M and [Cl2]=0.280 M. What is the concentration of the reactant, PCl5, at equilibrium?
1. The equilibrium constant, Kc, for the reaction PC13(g) + Cl2(g) = Pcl3(g) equals 49 at 230°C. If 0.400 mol each of phosphorus trichloride and chlorine are added to a 4.0-L reaction vessel, what is the equilibrium composition of the mixture at 230°C?
The equilibrium constant for the following reaction is 1.20×10-2 at 500K. PCl5(g)<----->PCl3(g) + Cl2(g) If an equilibrium mixture of the three gases at 500K contains 2.37×10-2 M PCl5(g) and 1.04×10-2 M PCl3, what is the equilibrium concentration of Cl2? ___ M
Consider the reaction: SO2Cl2(g) SO2(g) + Cl2(g) A reaction mixture contains an initial concentration of [SO2Cl2] = 0.020M. At equilibrium, [Cl2] = 1.2 x 10-2 M. Calculate the value of Kc.
Consider the reaction: PCl5 (g) ⇔ PCl3 (g) + Cl2 (g) The initial concentration of PCl5 is 0.40 M and the equilibrium concentration of PCl3 is 0.33 M. Calculate the equilibrium constant Kc.
For the equilibrium PCl5(g) PCl3(g) + Cl2(g), Kc = 2.0 × 101 at 240°C. If pure PCl5 is placed in a 1.00-L container and allowed to come to equilibrium, and the equilibrium concentration of PCl3(g) is 0.27 M, what is the equilibrium concentration of PCl5(g)?
The equilibrium constant, K, for the following reaction is 1.20x10-2 at 500 K. PC15(E) =PC13(E) + Cl2(E) An equilibrium mixture of the three gases in a 1.00 L flask at 500 K contains 0.157 M PCI3, 4.34x102 MPC12 and 4.34x102 M CI, What will be the concentrations of the three gases once equilibrium has been reestablished, if 3.17x10 - mol of Cl2(g) is added to the flask? [PC13] = [PC13] = [Cl] =