Question

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In the laboratory you are given the task of separating Ba2+ and Co2+ ions in aqueous solution. For each reagent listed below indicate if it can be used to separate the ions. Type "Y" for yes or "N" for no. If the reagent CAN be used to separate the ions, give the formula of the precipitate. If it cannot, type "No" Y or N Reagent Formula of Precipitate if YES K2S КСІ КОН

Answer 1

K s (aq) + Ba+2 (aq) -------> Bas (aq) + 2 K+ (aq) Kys (aq) + Co+2 (aq) ------> COS (s) + 2 K+ Co+2 forms Cos (precipitate) and Bat2 cannot. Answer: YES Formula of the precipitate = Cos 2 KCl (aq) + Ba+2 (aq) -------> BaCl, (aq) + 2 K+ (aq) 2 KCl (aq) + Co+2 (aq) ------> CoCl2 (aq) + 2 K+ Co+2 and Ba+2 cannot form precipitate. Answer: NO 2 KOH(aq) +Ba+2 (aq) -------> Ba(OH)2 (aq) + 2 K+ (aq) 2 KOH(aq) + Co+2 (aq) ------> CO(OH), (s) + 2 K+ Co+2 forms CO(OH), (precipitate) and Ba+2 cannot. Answer: YES Formula of the precipitate = Co(OH)2

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2 NaCl (aq) +Ba+2 (aq) -------> BaCl2 (aq) + 2 K+ (aq) 2 NaCl (aq) + Cu+2 (aq) ------> CuCl2 (aq) + 2 K+ (aq) Cu+2 and Ba+2 cannot form precipitate. Answer: NO 2 KOH (aq) +Ba+2 (aq) -------> Ba(OH)2 (aq) + 2 K+ (aq) 2 KOH(aq) + Cu+2 (aq) ------> Cu(OH), (s) + 2 K+ Cu+2 forms Cu(OH)2 (precipitate) and Ba+2 cannot. Answer: YES Formula of the precipitate = Cu(OH)2 Na S02 (aq) + Ba+2 (aq) -------> BaSO4(s) + 2 Na+ (aq) Na2SO4 (aq) + Cu+2 (aq) ------> CuSO4 (aq) + 2 K+ Ba+2 forms BaSO4 (precipitate) and Cut2 cannot. Answer: YES Formula of the precipitate = BaSO4