∆G=∆G°+RTlnQ
∆G=0, implies ∆G°=-RTlnk at equilibrium(Q=k).
K=2.07*10-12
R=Universal Gas Constant=8.314J/mol K
T=Temperature=298K
So ∆G°=-R*T*ln(K)
∆G°=-8.314*298*ln(2.07*10-12)
=66.65KJ/mol
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