The relevant reaction is 10- Calculate Ke for this equilibrium at 25°C. Kp for the reaction...

Question

Question

The relevant reaction is 10- Calculate Ke for this equilibrium at 25°C. Kp for the reaction of SO(g) with O, to produce SOS)

Answer 1

Answer #1

Answew 25°29 + 02g) - 28039) The relation between Kp and ke is geven as Kp = Kc CRT) on {kp.= 8x10243 on = difference in mole

Answer 2

Similar Homework Help Questions

2. How is the equilibrium-constant expression (Kc) for the reaction: 2NO(a) = N2() + Ke=0.145; related...

2. How is the equilibrium-constant expression (Kc) for the reaction: 2NO(a) = N2() + Ke=0.145; related to the following reaction? O2 (a) N2(a) + O2(a) = 2NO(a) K=.............. (b) 4NOQ = 2Nz () + 2O2(g) Kos......... (c) NO) 1/2 N2(0)+ 1/2O2(0) K3= +++ (d) 1/2 N2(a) + 1/2O2(a) = NO) Ke=.............. 3. Given Kc or ko for the following reactions, what is the value of Koor K? (a) l2(g) + Cl2(a) = 2ICIOX Kc = 2.0 x105 at 25°C (b)...
At 25°C the equilibrium constant (Kp) for following reaction is 4.5% 10% the 2NO(g) = No...

At 25°C the equilibrium constant (Kp) for following reaction is 4.5% 10% the 2NO(g) = No (9) + Oo (9) _ If the initial pressure of NO cg) befor any products have I been formed is 9.5 atm, what are the equilibrium partial pressures of Na(g), O2 (g), and Norg) ?
Consider the equilibrium 4. N2(g) 02(g) Br2(g) 2NOBr (g) Calculate the equilibrium constant Kp for this reaction, give...

Consider the equilibrium 4. N2(g) 02(g) Br2(g) 2NOBr (g) Calculate the equilibrium constant Kp for this reaction, give the following information (298.15 K) NO (g) +1/2Br2(g) NOBr(g) Ke 4.5 2 NO (g)N2(g) 02(g) Ke 3.0 x 102 5. For the BrCl decomposition reaction 2BrCl(g) Br2(g Cl2(g) Initially, the vessel is charged at 500 K with BrCl at a partial pressure of 0.500 atm. At equilibrium, the partial pressure of BrC is 0.040 atm. Calculate Kp value at 500K Consider the...

283.3 for the equilibrium reaction below at 131.8 °C, find Ke If Kp = 2H2(g)2g)=2H20()

283.3 for the equilibrium reaction below at 131.8 °C, find Ke If Kp = 2H2(g)2g)=2H20()
3. (a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25°...

3. (a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: 4 NO (g) → 2 N2O (g) + O2 (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction product favored? Compound ∆ Ho , kJ/mol S o , J/mol• K NO (g) 90.9 210.76 N2O (g) 82.05 219.85 O2 (g) 0 205.14
For the equilibrium reaction, 2 S03 - 2 SO2 (g) + O2 (g), Kc is 4.08...

For the equilibrium reaction, 2 S03 - 2 SO2 (g) + O2 (g), Kc is 4.08 x10-3 at 1000 K. Calculate the value for Kp. (R 0.0821 L.atm/ mol.K) A. 9.60 B. 2.99 OC. 4.97 x 10-5 OD.0.335

(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C...

(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: C2H2 (g) + 2 H2 (g) → C2H6 (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction productfavored? Compound ∆ Ho , kJ/mol S o , J/mol• K C2H2 (g) 226.73 200.94 H2 (g) 0 130.68 C2H6 (g) -84.68 229.6
(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C...

(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: C2H5OH (g) → C2H4 (g) + H2O (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction productfavored? Compound ∆ Ho , kJ/mol S o , J/mol• K C2H5OH (g) -235.1 282.7 C2H4 (g) 52.26 219.56 H2O (g) -241.82 188.83
(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C...

(a) Use the data given below and calculate ∆Ho, ∆So, ∆Go, and Kp at 25° C for the reaction: C2H2 (g) + 2 H2 (g) → C2H6 (g) (b) Calculate ∆G for the reaction at 250 °C. (c) At what temperature (°C) is ∆G equal to zero? In what temperature range is this reaction productfavored? Compound ∆ Ho , kJ/mol S o , J/mol• K C2H2 (g) 226.73 200.94 H2 (g) 0 130.68 C2H6 (g) -84.68 229.6

The equilibrium constant Kp for the reaction 2H2O(g)--> 2H2(g)+O2(g) is 2x10^-42 at 25 degrees C. (a)...

The equilibrium constant Kp for the reaction 2H2O(g)--> 2H2(g)+O2(g) is 2x10^-42 at 25 degrees C. (a) what is Kc for the reaction at the same temperature? (b) the very small value of Kp (and Kc) indicates that the reaction overwhelmingly favors the formation of water molecules. Explain why, despite this fact, a mixture of hydrogen and oxygen gases can be kept at room temperature without any change.