Question

Q-2……………..By identifing the sprectra provide the information about the structure , Please provide the structure of the compound. Justification (i.e. shifts, multiplicities, peaks etc.) for your structure should be given.

13C NMR Spectrum (100.0 MHz, CDCI, solution) DEPT CH CH. CH 3395 solvent proton decoupled IR Spectrum liquid film) 1093 LLLLLLLLLLLL 20016012080 400 g (ppm) 4000 3000 2000 V (cm 800 1600 ) 1200 expansion expansions TH NMR Spectrum (400 MHz, CDCI, solution) 91 107 Mass Spectrum expansion 5.14 5.10 ppm 40 3.8 ppm 3.06 3.00 ppm | % of base peak 2H 166 7.3 7.2 ppm TMS M + LL Co H1102 40 80 200 240 280 10 9 8 7 6 5 4 3 2 1 120 160 m/e 8 (ppm)

Answer 1

Answer: Hey dear student find the solution of your query, if you have any doubt feel free to ask. Thanks!! As per given molecular formula of the compound = C,H,40, ► First we need to calculate the degree of unsaturation of the compound (DOU) = (Number of carbon atoms + 1) - (number of hydrogen atoms/2) DOU = (10 + 1) - 14/2 = 4 hence the compound is aromatic Peaks in IR spectrum: Functional group Frequency (cm) 3395 3100 2900 O-H stretching Aromatic C-H stretching C-H stretching -- for ether 1096 As per mass spectrum: Exact molecular structure of the compound and their fragmented product OH H2C-CH3 CH3 HAC-CH-0 m /z: 106.08 m/z: 92 Molecular Formula: C Ho molecular weight: 166.10 m/z: 166.10 (100.0%). Total number of signals in 'H-NMR present in the given spectrum is five OH 11 HỌC-CH-o 10 Number of proton assign 1, 2, 3, 4, 5 Chemical shift value(8 in ppm) 7.2 -73 5.14-5.10 4.00 -3.88 1.10 Splitting pattern multiplet (5H) triplet (1H) multiplet (4H) triplet (2H) 7, 10

Total number of signals in C-NMR present in the given spectrum is three. multiplicity Dept Number of carbon assign Chemical shift value (8 in ppm) 170 6 Aromatic quaternary C No peak 128.6 Aromatic CH 127.5 125.0 Aromatic CH Aromatic CH CH 103.6 Positive peak Positive peak Positive peak Positive peak Negative peak Negative peak Positive peak 63.0 CH 7 42.0 CH 15.5 CH On the bases of IR, Mass, 'H-NMR and "C-NMR the proposed structure of the compound: OH H2C-CH3 HAC-CH-O 1-ethoxy-2-phenylethanol