First we will find Molar Mass of Aluminium Hydroxide
Molar Mass of Aluminium Hydroxide Al(OH)3 = (1 x 27) + (3 x 16) + (3 x 1) g/mol
= (27 + 48 + 3) g/mol
= 78 g/mol
Now,
Percentage Composition of Aluminium = (Mass of Aluminium / Molar Mass of Al(OH)3 ) X 100
= (27 / 78) X 100%
= 34.6 %
Percentage Composition of Oxygen = (Mass of Oxygen / Molar Mass of Al(OH)3 ) X 100
= (48 / 78) X 100%
= 61.5 %
Percentage Composition of Hydrogen = (Mass of Hydrogen / Molar Mass of Al(OH)3 ) X 100
= (3 / 78) X 100%
= 3.85 %
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