Question

2. The value of an indicates the change in the number of moles of gas in the balanced chemical equation. Adjust An and observ

a. Predict what happens to the concentration of a gas (in moles per liter) when the container volume is increased. Adjust the

b. Complete this table detailing how Q is affected by a change in volume for various values of AN. Note that changing An caus

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Answer #1

2) ∆n= -1: 2Mg+ o2→2mgO. K= [mgo]^2/([mg]^2*[o2-])

∆n =o: caco3 + 2hcl→ cacl +CO2 + h2o. K= ([cacl2]*[CO2]*[h2o])/([caco3]*[hcl]^3).

∆n = 1: caco3→ CO2+ caO. K= ([CO2]*[caO]/[caCo3]

A) on increasing the volume of the container, the concentration of reactants and consequently that of products decreases, therefore, as per Lechatleliers Principle, the direction of the reaction shifts to the side where no. Of moles is less.

B) ∆n=-1 , decreases

∆n =0 stays same

∆n = 1, increass

C)Q only changes when K changes. Which in turn changes when the temperature or pressure or volume of the reaction system changes. If Q is less than K , more products will be formed, if more then, more reactants will be formed, if equal, then the reaction is at equilibrium.

D) negative: reactants | products | reactants

Positive: products | reactants | products

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