We know that,
Molar mass of Cl = 35.45g/mol
Molar mass of B4H9Cl = 87.77g/mol
From the stoichiometry of chemical formula (B4H9Cl)
1 mole Cl is contained from 1mole B4H9Cl
Or
1 mole Cl is obtained from 1 mole B4H9Cl
So,
35.45g of Cl is obtained from 87.77g of B4H9Cl.
Or
1g of Cl is Obtained from (87.77/35.45)g of B4H9Cl
So,
10.9g of Cl is Obtaiu from (87.77/35.45)×10.9g of B4H9Cl .
Amount of B4H9Cl = (87.77/35.45)×10.9g
Amount of B4H9Cl = 26.99g
Answer = 26.99g
Use the References to access important va An experiment requires that enough B.H,Cl be used to...
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