Question

Use the References to access important va An experiment requires that enough B.H,Cl be used to yield 10.9 g of chlorine. How
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Answer #1

We know that,

Molar mass of Cl = 35.45g/mol

Molar mass of B4H9Cl = 87.77g/mol

From the stoichiometry of chemical formula (B4H9Cl)

1 mole Cl is contained from 1mole B4H9Cl

Or

1 mole Cl is obtained from 1 mole B4H9Cl

So,

35.45g of Cl is obtained from 87.77g of B4H9Cl.

Or

1g of Cl is Obtained from (87.77/35.45)g of B4H9Cl

So,

10.9g of Cl is Obtaiu from (87.77/35.45)×10.9g of B4H9Cl .

Amount of B4H9Cl = (87.77/35.45)×10.9g

Amount of B4H9Cl = 26.99g

Answer = 26.99g

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