Question

If 1.80 g of a compound containing only Carbon and hydrogen occupies 1.4 L at 0.00°C and 775 mm Hg, what is the molecular formula of the compound?

A) CH4

B) C2H6

C) C2H4

D) C2H2

E) C3H6

Answer 1

molecular formula of the compound is C2H4

Ans weni- weight of the compound = 1.80 g lblume of the compound = 1044 we know from the mole concept. moles terms of the volume is defined as Volume of the compound 24.4 L. of the compound in 1.4L 22.4L moles of the molecule = 0.0625 mol Again we know that moles of the moletwe = weight of the compound molecular maus Hence moleculoos maus - weight of the compound moles of the given molecule 108 g 000625 mol molecular mass of molecule = 28.8 g/mol Given molecules and it molecular mars are C CH4 → molecular mass = l + 4 = 16 g) mol X B) Ca MG > moleculan mars = 2x13 +6 = 3.2 g/mol x (C) C244 molecular mars = 2X12 +4 = 28 g/mol r DJCg Hg = molecular masis = 9x12 + L = 26 g/mol x ) CZ M6 → molecular mare = 3x12. + 6 = 42 g/mol x we conlude from calculated molecular mars of the compound from given data the molecular formula of the compound is Cg 14