Homework Answers
no of moles of NaH2PO4 = molarity *volume in L
= 0.235*0.225 = 0.052875moles
no of moles of Na2HPO4 = molarity *volume in L
= 0.371*0.225 = 0.083475moles
no of moles of NaH2Po4 after addition of 0.0297 moles of HNO3 = 0.052875+0.0297 = 0.082575moles
no of moles of Na2HPo4 after addition of 0.0297 moles of HNO3 = 0.083475-0.0297 = 0.053775moles
PKa = 7.21
PH = PKa + log[Na2HPO4]/[NaH2PO4]
= 7.21 + log0.053775/0.082575
= 7.21 -0.1863
= 7.0237 >>>>answer
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