Question

calculate the amount of solid (in grams) that is produced when 18.00 mL of 0.1100 M sodiun chromate is mixed with 21.00 mL of 0.09300 M aluminum chloride.

write the balanced molecular and net ionic equations for this reaction. State the spectator ions left in solution

Answer 1

Balanced molecular equation: 2AlCl3(aq) + 3Na2CrO4(aq) = Al2(CrO4)3(s) + 6NaCl(aq)

Net ionic equation: 2Al3+(aq) + 3CrO42-(aq) = Al2(CrO4)3(s)

2 Aliz (aq) + 8 Naz Go On (aq) = Al₂ C Grou) (8) + 6 Nallfar) C = 0.093M C = O. JIM = 21 ml = 0.024 V = 18 ml > 0.0212 = 0.018 L .: No. of moles of Alca, (aq) = C, Ni = 0.093 mol/xx0.021 X = 1.953 x 103 mol Vom .. No. u u a Nag Crou (aq) = (V2 = 0.1l moll KX 0.018 K = 1.98*10-3 mol : No. of moles of Alz (coule produced from All, = 1.983 +10% • 1 mot = 0.9765x10 mot This comes from mole ratio of product & reactant-

... No. of moles of h Alz (Co Ou), produced from Naz Gron = /1.98% 10 3 x 1 mol = 0.66%d0-3 anol. This I comes from the pit-reactant ratio, was 0.9765*10-3 mols of Ala (60m), : Naz Gou a 0.66* 10 3 a n Ala (GO). ... Nazor Oy is the limitting neagent and Al Uz is the excess reagent. :.0.66x10 3 mots of Nors to 'Alz (G. Ou), are produced. Molar mass of Als (Gron) 3 = 400.9442 gen sunul 2. Amount of a Ala (GrOn)z produced = (401.9442 gan/mol x 0.66 x 103 mol) = 0.265 gm.
Spectator ions left in the solution are Na+ and Cl-.