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6. Consider the following equilibrium, 2N2(g) + 6H20(0) 4NH3(g) + 3O2(g) AH =-1531 kJ/mol a. Write...
6 (13 pts) Given the system: 4NH3(g) + 302(g) = 2N2(g) + 6H2O(1) AH=-1530.4 kJ a) Discuss and provide reasoning) how the ammonia (NH3) concentration will be affected at equilibrium: i) Removing 02: ii) Adding additional water: iii) Increasing volume:
Given the system: 4NH3(g) + 302(g) = 2N2(g) + 6H2O(1) AH=-1530.4 kJ a) Discuss (and provide reasoning) how the ammonia (NH3) concentration will be affected at equilibrium: i) Removing O2: ii) Adding additional water: iii) Increasing volume:
Consider the two reactions. 2NH3(g)+3N2O(g)4NH3(g)+3O2(g)⟶4N2(g)+3H2O(l)⟶2N2(g)+6H2O(l) Δ?∘=−1010 kJΔ?∘=1531 kJ2NH3(g)+3N2O(g)⟶4N2(g)+3H2O(l) ΔH∘=−1010 kJ4NH3(g)+3O2(g)⟶2N2(g)+6H2O(l) ΔH∘=1531 kJ Using these two reactions, calculate and enter the enthalpy change for the reaction below. N2(g)+12O2(g)⟶N2O(g)N2(g)+12O2(g)⟶N2O(g)
Consider the following reaction at equilibrium: 2CO2(g) = 200 (g) + O2(g) AH° = -514 kJ Le Châtelier's principle predicts that a decrease in temperature will decrease the value of the equilibrium constant O increase the value of the equilibrium constant decrease the partial pressure of CO increase the partial pressure of CO2 (g) decrease the partial pressure of O2 (g) Consider the following reaction at equilibrium: 2NH3 (g) = N2 (g) + 3H2(g) AH° = +92.4 kJ Le Châtelier's...
Version A 12. If AH = 75 kJ/mol and AS = 75J/mol K for an equilibrium reaction at 1400 K, describe the equilibrium constant K. (A) K=0 (B) 0<K<1 (C) K=1 (D) K>1 13. A perturbation of an equilibrium is observed to have caused additional products to form. The reaction is exothermic and has An = 2. Which of the following stresses could have caused the observation? (A) Increased Pressure (C) Removal of Product (E) None of these (B) Decreased...
Consider this system at equilibrium. A(aq) = B(aq) AH = -450 kJ/mol What can be said about Q and K immediately after an increase in temperature? OQ> K because Q increased. O Q> K because K decreased. O Q< K because K increased. O Q< K because Q decreased. OQ=K because neither changed. How will the system respond to a temperature increase?
45. Refer to the following equation: 4NH3(g) + 70,() → 4NO2()+6H20() How many moles of ammonia will be required to produce 10.5 mol of water a. 4.20 mol b. 10.5 mol c. 7.00 mol d. 5.25 mol e. none of these 46. Refer to the following equation: 4NH3(Ⓡ) + 702() → 4NO2(%) +6H20(g) How many molecules of NO2 are produced when 4.16 mol of ammonia is completely reacted a. 16.64 b. 5.01 X 1024 c. 2.51 1024 d. 191 e....
Consider the following system at equilibrium where K - 1.29x10- and AH = 108 kJ/mol at 600 K. COC12() CO(g) + Cl2 ) The production of CO (g) is favored by: Indicate True (T) or False (F) for each of the following: 1. increasing the temperature. 2. increasing the pressure (by changing the volume). 3. increasing the volume. 4. removing COCI2. 5. removing Cl2 Submit Answer Retry Entire Group 1 more group attempt remaining Consider the following system at equilibrium...
Consider the equilibrium in the reaction 3O2(g) 2O3(g), with reaction H 285.4 103 J mol–1 at 298 K. Assume that reaction H is independent of temperature. a) Without doing a calculation, predict whether the equilibrium position will shift toward reactants or products as the pressure is increased. b) Without doing a calculation, predict whether the equilibrium position will shift toward reactants or products as the temperature is increased. c) Calculate KP at 550 K. d) Calculate Kx at...
The decomposition of ammonia gas is endothermic, AH = 92 kJ/mol. 2 NH3() = N2(g) + 3H2(g) What change to an equilibrium mixture of this reaction will result in the formation of more hydrogen gas? The addition of a catalyst. An decrease in temperature. An increase in volume. A decrease in the concentration of ammonia.