Question

QUESTION 5 (A ) pH = pka + log THA) Use the Henderson-Hasselbalch equation to solve the following problem: A solution of hypoiodous acid (HIO, pka = 10.50) has a measured pH of 11.24. What is the % ionization of the hypoiodous acid? 58.71% 15.40% 84.60% O 73.44%

Answer 1

o HIO at to, c at taten ((1-0) H+ + 10 o cx coe where a in the extent of reaction. At equilibrium, [H] [10] K: THIO] CR.CO Kac (1-2) At equilibrium . . LHA - Given pka = 10.50 the concentration of Htion, Cx . & pH of the solution - 11.24. - 10.50 - 11.24 So Ka 2 10 & [H ] = 10 - 11.24 Car 10 & Cx.ca. = - 10.50 10 Ca.la -10.50 = 10 & (1-x) -10.50 Cx.x = 10 le - 11.24 - 10.50 10 = 10 x or, 0.74 BY, ole Tă = 10 -0.74 or, 1-8 - 10

or - 0.74 – - 1 = 10 or, L. 1.18497 or x = 0.8460 i. i The extent of reaction = 0.8460. The 1. ionization of the hypoiodous acid = xx 100%. = 0.84 60 x 100%, - 84.607 . The % ionization is 84.60%