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Calculate either H,Otor OH) for each of the solutions. Solution A: (OH) = 1.97 x 10-M Solution A: 1,0+1= Solution B: H0+1 =

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Relation between [thot] cont and = 10-14 m H40 I COM ] pH = pen= -log[H+] -log[on] pH <7 solution aceder Neutral pH = 7 PH> 7

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