Question

How many grams of Alz0, can be produced from 22.5 g Al? Enter your answer in the provided box. 4Al(s) + 302(g) → 2Al2O3(5) g Al2O3

Answer 1

501"=> How many grams of Alzoz can be produced from 22.5 gm Al ?. 4 Alcoy + 30zcan -> 2 Al2O3(5) =y Given mass of Al Caluminum) = 22.5 gm. Coulculate number of moles Of Al Caluminum). - 22.5 gm Al x 1 mole thon = 0.8333 mole Al 27 gm AT 11) converts moles of Al into moles of Al2O₃ ..0.8333 mole Al 2 " - X - mole of Alla -= 0.4166 mule 4 moje At Al2O3 iii) converts moles of Al2O3 into grams of AlzUz .. grams = Number of moles x molar mass. ... molar mass of Al2O3 = 102 gm/mole. (:. molar mass of Al=27X2=54 & molar mass of 0 = 16x3=48) i molar mass of Al223=54+48 = 102 golmule. :. grums of Ako3 = 0.4166 mole x 1029m) myle = 42.498 gm .. Grams of AlO3 = 142.498 | gm 142.5/gm