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Question 6 (1 point) When answering this problem, report the answer with the appropriate number of significant figures. When
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Answer #1

Solution-

Here we have the total volume = 10+ 20= 30 ml

The concentration of weak acid
M2= M1V1/V2 = (0.030*10)/(30)= 0.01 M

Concentration of weak base

M2= M1V1/V2 = (0.030*20)/(30)
=0.02 M

pKa of CH3COOH = 4.75

=> pH= 4.75 + log(0.02/0.01) = 5.05*10^0

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