Question

9. IF 0.10 mol of Carolts is treated with 0.160) mol of HCl gas, how many mols of Cach could be formed? 10. A monatomic species that has 18 electrons and a net charge of 2- (A) is iscelectronic with a neutral argon atom. (B) has more protons than electrons. (C) has 2 unpaired electrons. 11. 50.0 mL of H3PO, is titrated to the end point using 38.65 mL of 0.150 M of NaOH. Write the balanced reaction equation. Calculate the concentration of this acid. 12. Boron has two naturally occurring isotopes with the following masses and natural abundances. Mass (amu) Abundance (%) Boron-10 10.01294 19.922 Boron-11 11.00931 80.081 Calculate the average atomic mass of boron. You must show your work!

please explain how you found the answer

Answer 1

cacon) + au cach + 2H2O so Imol of calon) react with a mol of He to give imol of each now 0.10 mol of Caen), given which required - 2x0.10 mol of HI 0-20 met HU but mole of He given 0.160 mel it means less than ... required to react with it with calen), calen), so so he is limiting reagent. Hell is ll. now . amol of Ho give mole of cach ! so 0.160mol of the give = Imole of call2 X0:160 mole of the Imol of het 0.08 mole of cacy. Monoatomic speues = 18e & net charges-2 to have atomic number = 18 so it have 18 protond 1Delectron so (A) - correct statement as both have same number of electron. charge is it means more number of elections than proton. So wsong statement. O e o solelechon increased) 1.2 é (@) wrong as for 10e 15²25² 22635²3p6 so all are . paired. M₂ pou 340 + pouz . let H₂ pou am (M) 3XMAN - volume of Mapoy = 50.0mL at equivalence point, mole of (H+) = male of Cou) oy 3x mol x 50-omL X163L 38.6 SWL X16 SLX 150 m 1 The TL or 2= S-798 = 0.039 0.039m concentration of Mapoy=am = so ) Avy Atomic em, xabundance) + m2(abundance) = 10.01294X (19.222)+(11:00 mass 100 any + 88 1.636554 = 10.74 104 Camu) 192.467.964 + 881.636554 (07