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Data Table 1 Solution A.05M Acetic Acid IA (aq) + 1,0 (1) PH : 2.90 1,0 (aq) + (aq) 15 Molarity - Initial Concentration Chan

Data Table 3 Solution C 0.0125M Acetic Acid HA (aq) + H20 (1) PH = 3.16 + H30 (aq) + (aq) 0.0125 Molarity - Initial Concentr

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Table o Solution A 0.05m Acetic acid : ICE Table : H₂O lag) HA(aq) + HO () 2 0.05 Initial Change te th - ke 0.05- th tx EquilKa 1,26X173 x 1.26x103 0.0487 1-587 X 106 0.0487 32:59 x 10-6 ♡ 3.25x1651 Ka = 325X165 de cunin lo gonization (1507) vi = X lAt equilibrium [H₂ot) = x I 0:0011 and (HA) - 0.025 -x = 0.025-0.001 = 0.024 M1 Put in ② Ka = (0.001) (0.001) 1910 6 466x165Given pH = 3.16 [Hot] - 16H4- 17346 At equilibrium [tyof] = 6.98704M i.x= 6.98109 = 0.00069 - - 4 = 0.0125 - 0100069= 0.0118Solution ② 0.05M Sodium acetate : - (aq) + H₂O 0.05 Onitial HA + oH o o ta ta change -x x x Equilibrium 0.05- x x - [HA] [ot]Percent ioni gestion - baxti Percent ionization = 4700 2t/oo LA Ignition 5.138106 005 40 = 0.01% Percent ionizetim - 0-otofof

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