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Suppose a 500. mL flask is filled with 0.50 mol of H, and 1.7 mol of 12. The following reaction becomes possible: H2(g) +12(g

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= 3.4m v= 500 m2 = 1 L MHz = 0,6 = 1 MM I = 17 Hz Cgs + Iz cgj 7 2 HI Cg K= 3.3 3.4 (1-x) (3.4%) 2x to tt Now, LHIS = 3.3 [H.Please like the solution.Feel free to ask any doubt in comments.

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