Question

10. 111 BIL. 9.19 Calculate the concentration of oxygen in mil- ligrams per liter required to completely oxidize the following organic compounds. Also calcu- late the volume of air in liters per liter of solu- tion treated. Use 500 mg/L as the concentration of each compound.

Answer 1

Ans! Given, methyl terliansy C5H10 butyl ether (MIBE) Now; Сс Balancing the oxidation reaction, EshgO + 12 1202 ) scoat6 Hgo I mol . 65/mol smol Gmol MO Cave converting the moles in ing → 1 mol of esitgo reacts with is moles of 39 2 88g cq Higo 1000mg ? Imol Co toxo . imo esthe 19 4 88 ooo 3 le mooto, x sag op xlooog mig a good log 19 ? 24 0000-00g Now - 3r calculate the concentration 0 -12n. - 88000rag Caltig anar 240000 mg og CamScanner

Song Csi, o X240039 mg Oz Soong CSA -na 88000mg estigo = 136 3:6 mg 02. Therefore the concentration of one is 1363.6 ong It benzyl morphine, Ca4 Has Noz . Balaricing equation Cay Has No3 + 2802 - 24 Cost 11Hgot runs Imol 28001 : 24 mol 11 mal lomol Now, Converting the moles in my I mol of Cza Has Noz reacts with 28 . moles of Og, so that :: e24 Has No ₂ = 375000 mg νσω, 38902 1000g 28 mol O2 X Tmelon " 19 CS Scanned wog= 896000 mg CamScanner .

ncentration 3 Calculating the concentration 아영 3750oonig o Ha No.3---896000 ingoa 300 mg Cau Hax Nozar. 500mg C24 Has No3 .* 896000 mg og 375000mg cao Has Nos . 24os 2 1194-7 ong Oa, ... Therefore, So, The concentration of our t's 11947 bedpridil, caultza No © Balanceng oxidation reaction C24 H3 4 N2O + 405 24692 +14 Hyo + a nulis mol mol 24ml 14 mol amo! Now, for converting the moles in ing. 1 mol caq 1434 Ngo reacts with lots moles of or if . then, . C24H34' 1 C24H34 Nao = 366.000 mig . 09 - 9760 Domag Scanned with How can calculating the concentration of-o

366000 mg Coulte, NgO --- 976000 mg og soong Cantz No ... Soong Cach 34 N20 X 976000mg Op . 366000 mg Caq H3N2o. s 1338.3 mg **- toluene, itseb tal-H Balancing the oxidation reaction C7148 +90g -27 Coat 4 H2O . 1 mol gmol mol . 4 mol .. converting the moles in mg I moleft& reacts with a moles of 02. C78 = 92000 mg gmol og reacts with I mole of cq Hg 02= 288000mg calculate the concentration of Og 92000 mg Cyhę co - 228000 mg og soo mg (718-cn. 5oong Ca mg x 288000 mqoa 92000 mg CA 178 = 1565.2 mg Therefore, The concentration of os is. (1565.2 mg] Scanned with CamScanner