Question

The mass of NaHCO3 calculated in part d is pretty substantial. Do you think we really need to use that much NaHCO3 to make this buffer solution? Could we scale it back a bit? Of course! As long as the ratio [CO3 2]/[HCO3 - ] = 0.35 holds, we’ll still be preparing a buffer solution with pH = 9.8. For example, you could use 0.00035 moles of CO3 2- and 0.001 moles of HCO3 - . Calculate the masses of 3.5 x 10-4 mol Na2CO3 and 1 x 10-3 mol NaHCO3.

Answer 1

The mass of 3.5 X 10-4 mol of Na2CO3 is 0.0371 g.

The mass of 1 X 10-3 mol of NaHCO3 is 0.084 g.

mass of Naf Coz u 849 m) Molar mars of relay co s 100 g mot 3.5*10-4 mot of ma coz Ix 10 mood of Natico, (1 x 10 x 84)g = 0.0899 = (3.5*10* *106) 9 = 0.0374g mass of maz loz will be 0.03719 mass of Mattcoz will be 0.0899