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Use the standard half-cell potentials listed below to determine which the following metals will dissolve in...
Use the standard half-cell potentials listed below to determine which the following metals will dissolve in hydrochloric acid. Cl2(g) + 2e -- 2014(aq); E° = 1.36 V 2H+(aq) + 2e - H2(g); E° = 0.00 V OPt; E°(P+2+/Pt) = +1.19V O Ag; E°(Ag+/Ag) = +0.80V O Au; EⓇ(Au3+/Au) = +1.50V O Al; E(A13+/Al) = -1.66V O Cu; E(Cu2+/Cu) = +0.34V
Standard Electrode Potentials at 25?C Reduction Half-Reaction E?(V) F2(g)+2e? ?2F?(aq) 2.87 Au3+(aq)+3e? ?Au(s) 1.50 Cl2(g)+2e? ?2Cl?(aq) 1.36 O2(g)+4H+(aq)+4e? ?2H2O(l) 1.23 Br2(l)+2e? ?2Br?(aq) 1.09 NO3?(aq)+4H+(aq)+3e? ?NO(g)+2H2O(l) 0.96 Ag+(aq)+e? ?Ag(s) 0.80 I2(s)+2e? ?2I?(aq) 0.54 Cu2+(aq)+2e? ?Cu(s) 0.16 2H+(aq)+2e? ?H2(g) 0 Cr3+(aq)+3e? ?Cr(s) -0.73 2H2O(l)+2e? ?H2(g)+2OH?(aq) -0.83 Mn2+(aq)+2e? ?Mn(s) -1.18 How can the table be used to predict whether or not a metal will dissolve in HCl? In HNO3? Drag the terms on the left to the appropriate blanks on the right to...
O H20 - 2.5 QUESTION 11 Use the standard half-cell potentials listed below to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25°C. (The equation is balanced.) Mg(s) + Cu2+(aq) Cu(s) + Mg2+(aq) E --238 V E° - +0.34 V Mg2(aq) + 2e - Mg() Cu2(aq) 2e-Cus) O A -2.04 V OB.-1.36 V OC. +2.04 V D. +2.72 V E. +1.36V Click Save and Submit to save and submit. Click Save All Answers...
Given the following standard reduction potentials choose the cell which will work as a voltaic cell. All cells below are written according to the usual cell diagram convention. Cu2+(aq) + 2e → Cu(s) E° = 0.34 V 2H+(aq) + 2e → H2(g) E° = 0.00 V Sn2+ (aq) + 2e → Sn(s) E° = -0.14 V Ni2+(aq) + 2e → Ni(s) E° = -0.26 V Cd2+(aq) + 2e → → Cd(s) E° = -0.40 V Sn(s) | Sn2+(aq) || Ni2+(aq)...
Part A Use the standard hall-cell potentials listed below to calculate the standard cell potential for the following consumo Mg(s) + Cu2+ (aq) Cu(s) + Mg(4) Mg2 (na) + 20 Mg(s) E--238 V Cuzaq) +20 - Cu(s) E' = 40.34 V O2.72 V 204 V -1.36 V 204 V O 1.36 V Submit
Part A Use the standard hall-cell potentials listed below to calculate the standard cell potential for the following consumo Mg(s) + Cu2+ (aq) Cu(s) + Mg(4) Mg2 (na) + 20 Mg(s) E--238 V Cuzaq) +20 - Cu(s) E' = 40.34 V O2.72 V 204 V -1.36 V 204 V O 1.36 V Submit
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy AG for the following redox reaction Round your answer to 3 significant digits. 2CH(OH), (-) +100H(aq) + 3Br (1) ► 2010 (92) +8H,O()+6Be (aq) cil Data E (V) 0.7996 x 5 ? -1.675 1.692 1.498 -2.912 1.066 1.35827 Half-Reaction Agt (aq) + e -- Ag (s) AP+ (aq) + 3e" -Al(s) Aut (aq) + e - Au (s) Au3+ (aq) + 3e" - Au (5)...
Using the table below: 19. Three combinations of metals are listed below, which combination would produce the largest voltage if they were used to construct an electrochemical cell? Copper (Cu) with zinc (Zn) Lead (Pb) with zinc (Zn) Lead (Pb) with cadmium (Cd) Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e +...
can you answer questions 7,8,9,10 Question 7 (10 points) ✓ Saved (7) For a galvanic cell notation: (-) Mg/Mg2+ (aq) // Cu2+ (aq) / Cu (+). which of the following is fully correct? (a) Mg2+ is oxidized to Mg, and Cu2+ (aq) is reduced to Cu O (b) Mg2+ is reduced to Mg, and Cu2+ (aq) is oxidized to Cu (c) Mg is oxidized to Mg2+, and Cu²+ (aq) is reduced to Cu (d) Mg is reduced to Mg2+, and...
please answer the full question. 2. You measured cell potentials (voltages) for reactions of metals and metal ions. We will use the standard date and practice calculating these. Recall: E-Ecathode - Eanode Remember reduction occurs at the cathode; oxidation occurs at the anode For the anode reactions, your reactant will be on the product side of the standard equation, but don't change any sign. The equation does that for you. Cathode Reaction Agt + e → Ag Ecathode Anode Reaction...