Question

Could someone help me draw out the mechanism for this reaction? This was the description of the steps...

Step 1) Ring opening of aziridine + MeOH addition

Step 2) Acetylative debenzylation with Pd(OH)2 and acetic anhydride

Step 3) Treatment with benzylamine in presence of Me3Al

Scheme 3. Synthesis of (R)-1 from Aziridine-(2R)-carboxylate 10 PAN1 Meo HÑ BF3E12 OEt MeCN MeOH 90 °C, 3 h 93% OEt PdfOAC)2/C Meo Ac20, ETOH rt, 12 h OET DIN MOY NHBn HÑO Me:AI HNO DCM rt, 3 h (R)-12 81% h 95% (R)-1

Answer 1