Question

- Estimate, as precisely as you can, the frequency, in cm-, for the radiation absorbed in the J = 0 → J = 1 transition for 13C160. State/justify any assumptions made for this calculation.

Answer 1

To answer this question we assume that bond length of 13C16O is same as that for 12C16O.

to for J=0 DE 2=0J=1 J=1 the change in enchy = B (J+1) J – B (Š +1)]" g" J' represent represent ground encired state state. = B(1+1)! - B (0+1)0 DE = 2B (B in cm) DE represent frequency: for calculation of B 34 B = h where = planks constant = 6.6410 usic I= urt- reduced muss c= veloury of eight = 3x10 m/sec Ran?ic = h = 872x² cm. m2) 80² 42c There is no other data is given for calculation a e. So we assure it ú equal to bond length observed in 1266 which is equal to 1.54A mi e me are mass of Bet 160 respectively. B= 6.64 10 34 Josee 8x3.14 * 3.14 * | 13 x 16 ) amu xl 15 4x108) x 3 x 10 msec Now, 8x3.14 x 3.14 × 1 13x16 Lan T 13+16 xli rux 7 = 1.6x16 34 Ja see 813 14 x 3 14x/13 x 16 ) x1681 x 16 2 1 3 4 15 4 x 150) 2 m2 x 3 x 100 cm sect 113+16) = Tidak J x 167 xi-surrisu ko kayang 6.6 x 10² 8x3-14X3 14 x13x16x1'67x15 4x4 (13 +16) X 3 frequency = 0.9818 unt S Jseca - kgmiz lamu 167 X10