Homework Answers
1)
In reaction Cr2+ is being oxidised to Cr3+
The reaction at anode is:
Cr2+(aq) -> Cr3+(aq) + e-
2)
In reaction Br2 is being reduced to Br-
Br2(l) + 2e- -> 2 Br-(aq)
3)
electron are absorbed at Br2 electrode and given out at Cr2+
electrode
So,
In the external circuit, electrons migrate (from) the Cr2+,Cr3+
electrode (to) the Br2 electrode.
4)
Anion flow opposite to electron to maintain charge neutrality. So,
Br2 will release anion
(To) the salt bridge (from) the Br2 compartment
Add Answer to:
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