Zn(CN)2(s) <---------------> Zn^+2 (aq) + 2CN- (aq)
Ksp = [Zn2+][CN-]^2 = x × (0.0390) ^2
Let x is the concentration of zinc ions.
Since 1 unit NaCN has 1 unit CN- ions.
So, 0.0390M has 0.0390 M CN-
So, now
8.0 ×10^-12 = x(0.0390) ^2
X = 5.3 × 10^-9 M
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