Which of the following demonstrates an E1cb reaction? HCI NaOE lot SOCI2 garage non or NaOH

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Answer 1

Answer #1

Answer: (d) option is correct.

explanation:

In the E1CB reaction, one has to ensure that there should be an anion stabilising group/atom in conjugation with leaving group.

Here ,in the above case , the anion stabilising group is =CO (carbonyl) which is in conjugation with -OH in the only option (d) ,

However, in other given options ,there is no anion stabilising group/atom is in conjugation with -OH

This is why ,(d) is the correct option.

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Answer 2

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