PART A :
1 INCH OF HG =0.03342 ATM
HENCE GIVEN 24.4 IN SO
PRESSURE IN ATM = 0.03342 *24.4=0.8154 ATM
PART B :
1 IN OF Hg= 25.4 mm OF Hg
HENCE 24.4 in of Hg = 24.4*25.4 mm of Hg
Pressure = 619.76 mmHg
Part C:
1inch of Hg = 0.4911 pounds per sq inches.
hence 24.4 inch of Hg = 24.4 * 0.4911 =11.9828 pounds per sq inches
PART D:
1 inches of Hg = 3386.39 Pa
hence 24.4 inches of Hg= 24.4*3386.39 Pa
pressure= 82627.916 Pa
< Problem Set #11 (Ch 11) Exercise 11.29 Rev The pressure in Denver, Colorado (5280-ft elevation),...
The pressure on top of Mount Everest (29,029 ft) averages about 235 mmHg Part A You may want to reference (Pages 201 - 201) Section 5.2 while completing this problem. Convert this pressure to torr. 10 AO + O 2 ? P- torr Submit Request Answer Part B Convert this pressure to psi. VALORO? P = Submit Request Answer Part 6 Convert this pressure to in Hg. Exercise 5.26 - Enhanced - with Feedback The pressure on top of Mount...