Ans number of unpaired electron =0
What is the number of unpaired electrons in strong field-[Fe(SCN) 1-5 2.1 3-0
QUBOOO 1 O unpaired electrons 1 unpaired electron 2 unpaired electrons 3 unpaired electrons 4 unpaired un electrons 5 unpaired electrons Submit Request Answer
If CN- is a strong field ligand, rank the following coordination compounds in order of decreasing number of unpaired d-electrons: [Fe(CN6)]3- [Pd(CN6)]2- [Mo(CN6)]4-
4. Highest possible oxidation State of Vanaalum IS 5. No. of unpaired electrons present in Fe atom = and hence it is magnetic. No. of unpaired electrons present in Fe3+ ion and hence it is magnetic.
b) By using crystal field theory, determine the configuration, the number of unpaired electrons, and the ligand field stabilization energy (LFSE) as a multiple of A, for the following complexes. (2 x 3 = 6 marks) (O) (Cr(NH3).]** (ii) [W(CO).)
In the complex ion [ML6]n+, Mn+ has five d electrons and L is a strong field ligand. According to crystal field theory, the magnetic properties of the complex ion correspond to how many unpaired electrons? A. 0 B. 1 C. 2 D. 3 E. 5 Which one of these complex ions would absorb light with the shortest wavelength? A. [Co(H2O)6]2+ B. [Co(NH3)6]2+ C. [CoF6]4– D. [Co(CN)6]4– E. [Co(en)6]2+ The ion [Co(NH3)6]2+ is octahedral and high spin. This complex is (4pts)...
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IF CN is a strong field ligand, rank the following coordination compounds in order of decreasing number of unpaired d-electrons: [Fe(CN) [Pd(CN) [Mo(CN)
Give the number of unpaired electrons in octahedral complexes with weak-field ligands for: a) Mn3+ b) Co3+ c) Rh3+ d) Ti2+ e) Mo2+
(b) Determine the oxidation state of the metal, the d electron configuration, the number of unpaired electrons and the ligand field stabilisation energy for the following complexes: (i) [Co(NH3)5Br]2+ (ii) [MnO4]- (iii) [Fe(CN)6]3- (iv) [Cu(H2O)6]2+
If CN- is a strong field ligand, rank the following coordination compounds in order of decreasing number of unpaired d-electrons: [Fe(CN6)]3- [Pd(CN6)]2- [Mo(CN6)]4- Group of answer choices [Fe(CN6)]3- > [Mo(CN6)]4- > [Pd(CN6)]2- [Mo(CN6)]4- > [Fe(CN6)]3- > [Pd(CN6)]2- [Pd(CN6)]2- > [Fe(CN6)]3- > [Mo(CN6)]4- [Fe(CN6)]3- > [Pd(CN6)]2- > [Mo(CN6)]4- [Mo(CN6)]4- > [Pd(CN6)]2- > [Fe(CN6)]3-
If CN is a strong field ligand, rank the following coordination compounds in order of decreasing number of unpaired d-electrons: [Fe(CN)]3- [Pd(CN)]2- [Mo(CN6)]4- [Mo(CN)]4-> [Fe(CN6)13-> [Pd(CNG)]2- [Pd(CNG)]2- > [Fe(CNG)]3-> [Mo(CNG)]4- [Mo(CNG)]4-> [Pd(CNG)]2-> [Fe(CNG)]3- O [Fe(CN)]3-> [Mo(CNG)]4-> [Pd(CNG)]2- O [Fe(CNG)]3-> [Pd(CNG)]2-> [Mo(CN6)]4-