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A sample of O, (MM 32.00 g/mol) in the left side of the container below has a pressure of 6.8 atm. It is separated from the r
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Answer #1

This process happens at constant temprature

And no of moles also remains constant

So (pressure initial)×(volume initial)=(pressure final)×(volume final)

Final volume will be 4+2.3 l =6.3 l since gas is expanded in whole container

Put these values in equation

6.8×4=p2×6.3

P2=4.3 atm

Hence final pressure is 4.3 atm

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