Question

The 1995 Nobel Prize in Chemistry was shared by Paul Crutzen, F. Sherwood Rowland, and Mario Molina for their work! concerning the formation and decomposition of ozone in the stratosphere. Rowland and Molina hypothesized that chlorofluorocarbons (CFCs) in the stratosphere break down upon exposure to UV radiation, producing chlorine atoms. Chlorine was previously identified as a catalyst in the breakdown of ozone into oxygen gas. Using the enthalpy of reaction for two reactions with ozone, determine the enthalpy of reaction for the reaction of chlorine with ozone. (1) CIO(g) +0,(E) Cl(g) +20,(6) AH;O= -122.8 kJ (2) 20,($) — 30,(8) AHin = -285.3 kJ (3) 03 (8) + C2(g) → CIO(g) + 0,(8) AHX = ? AH =

PLEASE help with these 3 questions
thanks in advance

none of the specific heat is given. The questions I guess is complete like that.
PLEASE help me

Answer 1

Question 1

We can change the equation as follow  

Reverse the first equation  

Cl (g) + 2O2(g) ====> ClO(g) + O3 (g)    ΔH = + 122.8 kJ

2O3 (g) ======> 3O2 (g)     ΔH = -285.3 kJ

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O3 + Cl (g) ======> ClO(g) + O2 (g)     ΔH = -162.5 kJ

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ΔH of the reaction is -162.5 kJ

Question 2

Let us calculate the amount of heat relased by 5.5 g of C6H6

Mass of C6H6 (Benzene) = 5.5 g

Molar mass of Benzene = 78 g/mol

Moles of Benzene = 5.5 g / 78 g/mol = 0.0705 mol

2 mole of benzene will release 6542 kJ

Amount of heat released by 0.0705 mol = 6542 x 0.0705 mol / 2 mol = 230.647 kJ

Using the heat let us calculate the final temperature  

the formula is

Q = mc∆T

Q = heat energy (Joules, J), m = mass of a substance (g)

c = specific heat (units J/g∙°C), ∆ is a symbol meaning "the change in"

∆T = change in temperature (°C Celcius)

Q = 230647 Joules m = 5691 g c = 4.184  J/g∙°C Ti = 21 °C

230647 J = 5691 g x 4.184  J/g∙°C x (Tf- 21 °C)

Tf = 30.69°C

Hence the final temperature of water is 30.69°C