Question

I'm not sure how to do the second part of this problem. I'm not sure how to draw the product of the isomers and what the third one may be. Thank you for the help in advance!!

7:07 PM Mon Mar 30 90% Wittig Final Reportsfors On-Line :D of Liquid+Unknown Wietig Alexis Smith Witting Pre-Lab 1. Complete the chart below with the relevant information for your reagents benzyl bromide 171.041.44 0.0025 mol g/mol g/cm3 triphenyl phosphine 1622 0.0034 mol mol trans-Cinnamaldehyde 132.1005 0.0015 mol 0.18 mk. 1.059 G/mol g'cm3 custo Poles to use 0.3 mak. 7.. 1 mode=0.0025mal cm 0.909. 1 mol = 0.0034 mol 1 262-298 Imt 132.neg 1 mol -0.0015 mol 2. Draw both possible stereoisomers of the product. Label each structure using EZ notation. Write the melting point of each isomer below its structure. [Note that there are actually 3 possible stereoisomers, but one is unknown and apparently cannot form because of steric crowding by the benzene rings. Draw its structure as well.] CHEM 373 Wittig Report

Answer 1

CHAPPhz Bro SH сH=си и се 2. base Phosphaniah sult benzalde fyue - cinna Maldehyde stereo Isomers: e both - possible X - regte I Ć=c " czet cis-cinnatralde hyde Melting points boiling point: 245-2460 Trans - cinnamal defycle. Melting point: -7.5°C

Third 18oner =CH₂