QUESTION 21 What volume of a 0.100 M HCl solution is needed to prepare 0.133 L...

Question

Question

Answer 1

Answer #1

Given , 0.1M solution to prepare 1.5M HCl soltion 0.133 L.

Using formula ,

M1V1 = M2V 2

(0.1 M) *(V ) = ( 0.133 L ) * ( 1.5 M )

V = 1.995

V = 2 approx .

Answer 2

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