Answer: 768 g of O2
Calculation and explanation:
Mol. Wt. of O2 = 16x2 =32 g/mole.
The reaction is
NaClO4 (s)
NaCl (s) + 2O2 (g)
1 mole 1mole 2 moles
According to stoichiometry of the reaction
1 mole NaClO4 produced 2 moles of oxygen
2 x32 g of oxygen
So, 12 moles NaClO4 will produce 2 x 32 x 12 = 768 g of O2
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