Question

Arrange the following 0.10 M solutions in order of decreasing pH (highest to lowest): NaCIO, KCI, HBr, NaBro, CH3NH3Br NaBro > NaCIO > KCI > CH,NH,Br > HB Nacio > CH,NH3Br > NaBro > KCI > HBr CH, NH,Br > NaBrO > Nacio > KCI > HBO Nacio > NaBro > KCI > CH,NH,Br > HBO NaBro > CH NH,Br > NaCIO > KCI > HBO

Answer 1

Arrange the following reactions in order of increasing tendency to proceed to completion (least greatest tendency) 1. 2NO3(8) = 2NO2(g) + O2(g) K - 1.4x10-3 II. 2HF8) = H268) + F2(8) K - 1.0x 10-2 III. N204(8) = 2NO2(g) K - 4.7x10-6 IV. 2H2S(3) = 2H2(8) + S2(8) K -2.4*10-4 IV <11 <1 < 111 II < IV < III III IV <1 < 11 III <IV < III III < 11 <1 < IV

Which two of the following salts will form basic solutions in water? NH4Cl, NaF, Lil, KNO3, KCN Lil, KNO3 NaF, Lil NHACI NaF, Lil, KNO3, KCN NH4CI, NaF, Lil NaF, KCN

Arrange the following 0.10 M solutions in order of decreasing pH (highest to lowest): NaCIO, KCI, HBr, NaBro, CH3NH3Br NaBro > NaCIO > KCI > CH3NH2Br > HBO Nacio > CH,NH3Br > NaBro > KCI > HBr CH, NH,Br > NaBrO > Nacio > KCI > HBO Nacio > NaBro > KCI > CH,NH,Br > HBO NaBro > CH NH,Br > NaCIO > KCI > HBO

Explanation :

1) HBr is the strongest acid. so it has lowest pH .

CH3NH3Br is the salt of strong acid and weak base . so pH < 7

KCl is the salt of strong acid and strong base .so pH = 7 .

NaClO and NaBrO are the salts of strong base and weak acids. so pH < 7 .

2)

NaF and KCN form basic solutions in water.

F- + H2O    --------> HF +   OH-

CN- +   H2O   ------------> HCN + OH-