Ka = 6.8*10^-4
pKa = -log(6.8*10^-4) = 3.1675
pH = pKa + log [F-]/[HF]
pH - pKa = log [F-] / [HF]
4.00 - 3.1675 = log [F-]/ [HF]
0.8325 = log [F-]/ [HF]
10^0.8325 = [F-]/0.100
6.799 = [F-]/0.100
[F-] = 0.6799 M
moles NaF = 0.6799 M x 2.00 L= 1.3598
Mass = moles * molar mass
mass = 1.3598 * 41.98 = 57.09 g
option (e) is correct. (nearest value)
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