Question

If a sample of C-14 initially contains 1.7 mmol of C-14, how many millimoles will be left after 2260 years?

Answer 1

Therefore, Concentration of C-14 left after 2260 years is 0.076 mmol

Answer) Half life of c-14 = 5,730 years Initial concentration [4.] = 1.7 mmol concentration at t= 2260 years [A+] = ? mmol 80 rate constant CK) can be calculated as K= ty k=0.69 K = 0.693 A- 5730 years k = 1.21 X10*4 years! Now, according to first order reaction k= 2.303 x log [As 1.218 10-4cyoaks) = 2:30 Cysew * long literaturan . 17mm 1. 21x10*** 2260 - log (1:14) – log [at] 2.303 1.187 = 0.068 - log [At] loo [At] = 0.068 - 1.187 [14] - Anblog (-1.119) [At] = 0.076 mmol Scanned with CamScanner