Theoretical mass = 0.213 and has a 67% yield, was is the actual mass?

Question

Question

Answer 1

Answer #1

- Ansi Actual % Yield = mass X100 theoritical mass 67 = 100 Actual mass 0 • 213 Actual mass = 67 0.213 100 = 0.142gm Actual m

Answer 2

Similar Homework Help Questions

First determine the actual yield, moles of Sr3(PO4)2 formed. From the actual yield, theoretical moles of...

First determine the actual yield, moles of Sr3(PO4)2 formed. From the actual yield, theoretical moles of limiting reactant in sample: a) Theoretical mass of limiting reactant b) Mass percent of limiting reactant in sample From the actual yield, mass of excess reactant sample, what is the mass percent of excess in sample? Beaker Sample II Unknown mixture NaPO412H2O * SrCl2* 6H2O Mass of mixture and container 113.4904g Mass of container 111.5575g Mass of mixture added to Beaker II 1.9329g Formula...
If the theoretical yield of a reaction is 21.1 g and the actual yield is 19.2...

If the theoretical yield of a reaction is 21.1 g and the actual yield is 19.2 g , what is the percent yield?
Lean 1 Learning Objective: 7J Distinguish between actual and theoretical yield to calculate percent yield Question...

Lean 1 Learning Objective: 7J Distinguish between actual and theoretical yield to calculate percent yield Question A0.156 g piece of solid aluminum reacts with gaseous oxygen from the atmosphere to form solid aluminum oxide. In the laboratory, a student weighs the mass of the aluminum oxide collected from this reaction as 0.1798- 1st attempt Part 1 See Periodic Table The 0.156 g solid aluminum is the Choose one: A theoretical yield B. excess reagent C. percent yield D. actual yield...

Please answer with explanation. akf1.amp The percent yield is calculated as follows: Actual yield Theoretical yield...

Please answer with explanation. akf1.amp The percent yield is calculated as follows: Actual yield Theoretical yield Percent yield (%) - The theoretical yield is the mass of product theoretically created as determined by the stoichiometry calculations The actual yield is the mass of product actually created in the lab when the experiment is performed. Assume the following reaction was completed in the laboratory: 6 Na(s)+ N(g)- 2 Na,N(s) 75 g of sodium, Na, reacted with 45 g of nitrogen, N,...
show your calculations for theoretical yield. Show calculations for percent yield of acetaminophen. Measured Mass of...

show your calculations for theoretical yield. Show calculations for percent yield of acetaminophen. Measured Mass of Limiting Reagent: 0.38 97 g (2 pts) 0.0646 g 12 pts) _(2 pts) Mass of Final product: Theoretical Yield: (2 pts) % Yield: Show your calculation for Theoretical Yield (using amounts actually measured in lab). Include full units and sig figs in all steps. (5 pts) 51.907 Show your calculation for % yield of Acetaminophen. Include formula in words. (5 pts) 0% yicla actual...
describe how the actual yield ( 1.48) compare to theoretical yield ( 1. 78 ) using the percent yield.

describe how the actual yield ( 1.48) compare to theoretical yield ( 1. 78 ) using the percent yield.

The theoretical yield of a reaction is 75.0 grams of product and the actual yield is...

The theoretical yield of a reaction is 75.0 grams of product and the actual yield is 42.0 grams. What is the percent yield? Select one: a. 31.5 b. 56.0 c. 178 d. 75.5 Which element can form an ion with a +2 charge? Select one: a. Mg b. o C. CI d. Al
A reaction has a theoretical yield of 16.5 g, but the percent yield is 80.1%. Select...

A reaction has a theoretical yield of 16.5 g, but the percent yield is 80.1%. Select the actual yield. 13.29 80.19 20.69 79.49
please calculate the theoretical yield and the percent yield!! RESULTS Mass of triphenylmethanol -__0.10 9 Theoretical...

please calculate the theoretical yield and the percent yield!! RESULTS Mass of triphenylmethanol -__0.10 9 Theoretical yield triphenylmethyl = bromide Mass of product = 0.149 (triphenylmethyl bromide) 9 Percent yield Melting point of product = 150.3 °C CALCULATIONS e triphenylmethanol x Imol triphenylmethanol x Imol triphenylmethyl bromide v 323.23g triphenylmethylbromide 260.33g triphenylmethanol 1 mol triphenyl methanol 1 mol triphenylmethyl bromide

How do I find the theoretical yield when I'm given the actual yield and limiting reactant?...

How do I find the theoretical yield when I'm given the actual yield and limiting reactant? It's for my lab problem which probably won't make sense but this is what it says: Theoretical yield of H2 (moles). Use Stoichiometry: Mg is limiting reagent