Calculate the pH and percent dissociation of 0.25 M NH3, Kb = 1.8 × 10^–5
Calculate the pH and percent dissociation of 0.25 M NH3, Kb = 1.8 × 10^–5
Part A: Calculate the pH of 0.61 M NH3 (Kb=1.8×10−5). Part B: Calculate the concentrations of all species present in 0.61 M NH3 (Kb=1.8×10−5).
Calculate the pH and percent dissociation of 0,25 M NH3, Ks- 1.8*10 8. Write the first and second dissociation reactions and the K, equations of each for carbonic acid, H2CO3. Kai -4.4 x 10- Ka) = 4.7 x 10-" 9. Classify the following salts as acidic, basic or neutral: (a) NaNO2 (b) NHACI (c) KF (d) KNO3 (e) NHC2H302 10. What is the pH of 0.35 M NH4Cl (salt solution)? Ks for ammonia (NH3) - 1.8 x 10-
Part A ) Calculate the pH of 0.20 M NH3 (Kb=1.8×10−5). Express your answer using two decimal places. Part B) Calculate the concentrations of all species present in 0.20 M NH3 (Kb=1.8×10−5). Express your answers using two significant figures separated by commas. Enter the concentrations of the species in the order listed below. [NH4+],[NH3],[OH−],[H3O+] = ?,?,?,?
Calculate the pH of a 0.401 M solution of NH4Br (Kb of NH3 = 1.8 x 10-5). Enter pH to 2 decimal places.
Calculate the pH of the following buffer system. 0.500 M NH3 ( Kb=1.8×10^(-5) ) 0.500 M NH4 Br A. 4.74 B. 9.26 C. 7.00 D.0.30 E. 13.70 I got 4.74
38. A buffer solution is 0.40 M NH3 and 0.60 M NHACI. Kb for NH3 is 1.8 x 10-5 a) Calculate the pH for the buffer system. b) Calculate the pH of the solution after adding 0.00600 moles of NaOH to 400.0 mL of the buffer. c) Calculate the pH of the solution after adding 0.050 moles of HCl to 600.0 mL of the buffer.
Calculate the pH of 0.25 M NH4CL given kb= 1.76x10^-5 for NH3 (ans. 4.92)
3) Kb for NH3 1.8 x 10-5 a) Calculate the pH of a buffer solution that is 0.100 M NH3 and 0.120 M NHANO3. b) What is the pH after 60.0 mL of 0.010 M HCl is added to 90.0 mL of the buffer solution in 2(a). Assume the change in volume is additive. c) What is the pH after 60.0 mL of 0.010 M Ca(OH)2 is added to 90.0 mL of the buffer solution in 2(a). Assume the change...
Calculate the PH of a 0.36 M aqueous solution of NH4NO3. Kb of NH3= 1.8 x10^-5. Please show your work; I know how to do a normal problem but I am confused because the Kb is only for NH3, not the whole thing. Thanks!
A 75.0-mL volume of 0.200 M NH3 (Kb=1.8×10−5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 13.0 mL of H