What is the mass of a cylindrical rod that has a diameter of 2.00 cm, height of 10.00 cm and a density of 11.35 g/cm3? Use 5 significant digits in your answer.
Given C= πd, A = πr2 , and V= πr2h
Formula
Density = Mass / Volume
Given,
height(h) = 10 cm
radius(r) = (diameter / 2 ) = (2 cm /2 ) = 1 cm
Volume = πr2h
= Volume = π × ( 1 cm )2 × (10 cm) = 31.4 cm3
density = 11.35 g/cm3
volume = 31.4 cm3
we know,
density = mass / volume
= mass = density × volume
= mass = 11.35 g/cm3 × 31.4 cm3
= mass = 356.39 g
Hence, the mass of the cylinder rod = 356.39 g
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