Homework Answers
no of moles of HX = W/G.M.Wt
= 3.55/29 = 0.1224moles
no of moles of NaX = W/G.M.Wt
= 2.90/51 = 0.057moles
PKa =-logKa
= -log(2.14*10^-5)
= 4.67
PH = Pka + log[NaX]/[HX]
= 4.67 + log(0.057/0.1224)
= 4.67-0.3319
= 4.3381 >>>>answer
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