The pressure of the gas inside the box is
$$ P=P_{\text {asw }}-\rho g(\Delta h) $$
Here \(P_{\text {otm }}\) is the atmospheric pressure, \(\rho\) is density of mercury, \(g\) is acceleration due to gravity, \(\Delta h\) is the height diffrence.
$$ \begin{aligned} P &=101.3 \times 10^{3} \mathrm{~Pa}-\left(13600 \mathrm{~kg} / \mathrm{m}^{3}\right)\left(9.8 \mathrm{~m} / \mathrm{s}^{2}\right)(0.1 \mathrm{~m}) \\ &=8.8 \times 10^{4} \mathrm{~Pa} \end{aligned} $$
What is the gas pressure inside the box shown in the figure? Pa=_____ What is the...
ion 13.3 Measuring and Using Pressure 6.)II What is the gas pressure inside .16 the box shown in Figure P13 y (cm) 100 75 50 25 Pgas Mercury 16 cm 6.0 cm 0 FIGURE P13.16 FIGURE P13.17 lad with o
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